Solution 2 to problem N1t6s11b4+5

Expressions | Parameters | Inequalities | Relevance | Back to problem N1t6s11b4+5

Expressions

The solution is given through the following expressions:


q28=0


q27=0


q26=0


q25=0


      2
     ---*p6*q1
      3
q24=-----------
        p3


q23=0


q22=0


q21=0


q20=0


q19=0


q18=0


q17=0


q16=0


q15=0


q14=0


q13=0


q12=0


q11=0


q10=0


q9=0


q8=0


q7=0


q6=0


q5=0


q4=0


q3=0


q2=0


p7=0


p5=0


p4=0


p2=0


p1=0

Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:

 q1, p3, p6

Inequalities

In the following not identically vanishing expressions are shown. Any auxiliary variables g00?? are used to express that at least one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3 means that either p4 or p3 or both are non-vanishing.

 
{q1,p6,p3,g0011*q1 + g0012*p3,q24}

Relevance for the application:

The system:


          2
b(1) =b(2) *p6
    t

b(2) =Db(2)*Db(1)*p3
    t

The symmetry:

        2      3
       ---*b(2) *p6*q1
        3
b(1) =-----------------
    s        p3

b(2) =Db(2)*Db(1)*b(2)*q1
    s

And now in machine readable form:

The system:

df(b(1),t)=b(2)**2*p6$

df(b(2),t)=d(1,b(2))*d(1,b(1))*p3$

The symmetry:

df(b(1),s)=(2/3*b(2)**3*p6*q1)/p3$

df(b(2),s)=d(1,b(2))*d(1,b(1))*b(2)*q1$