Solution 18 to problem l1o35
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Parameters |
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Expressions
The solution is given through the following expressions:
b75=0
b74=0
b73=0
b72=0
b71=0
b70=0
b69=0
b68=0
b67=0
b66=0
b65=0
b64=0
b63=0
b62=0
b61=0
b60=0
b59=0
b58=(a15*a7*b2)/a2**2
b57=0
b56=0
b55=0
b54=0
b53=0
b52=0
b51=0
b50=0
b49=0
b48=0
b47=0
b46=(3/2*a15**2*b2)/a2**2
b45=0
b44=0
b43=0
b42=0
b41=0
b40=0
b39=(a15*b2)/a2
b38=0
b37=0
b36=0
b35=0
b34=0
b33=0
b32=0
b31=0
b30=0
b29=0
b28=0
b27=0
b26=0
b25=0
b24=0
b23=0
b22=0
b21=0
b20=0
b19=0
b18=(3*a15*a7*b2)/a2**2
b17=0
b16=0
b15=0
b14=(2*a7*b2)/a2
b13=(2*a7*b2)/a2
b12=0
b11=0
b10=0
b9=0
b8=(5/2*a15**2*b2)/a2**2
b7=0
b6=0
b5=(5/2*a15*b2)/a2
b4=(5*a15*b2)/a2
b3=0
a22=0
a21=0
a20=0
a19=0
a18=0
a17=0
a16=0
a14=0
a13=0
a12=0
a11=0
a10=0
a9=0
a8=0
a6=0
a5=0
a4=3/2*a15
a3=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
b2,a7,a15,a2
Relevance for the application:
/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\$
3 2
df(u,t)=u *a2 + ---*u *a15 + f(v ,v )*a7
3x 2 x x x
df(v,t)=u *v *a15
x x
2 5 2 5 3 2
df(u,s)=(u *a2 *b2 + 5*u *u *a15*a2*b2 + ---*u *a15*a2*b2 + ---*u *a15 *b2
5x 3x x 2 2x 2 x
+ 3*u *f(v ,v )*a15*a7*b2 + 2*f(v ,v )*a2*a7*b2
x x x 2x 2x
2
+ 2*f(v ,v )*a2*a7*b2)/a2
x 3x
3 2 2
u *v *a15*a2*b2 + ---*u *v *a15 *b2 + v *f(v ,v )*a15*a7*b2
3x x 2 x x x x x
df(v,s)=---------------------------------------------------------------
2
a2
df(u,t)=df(u,x,3)*a2 + 3/2*df(u,x)**2*a15 + f(df(v,x),df(v,x))*a7$
df(v,t)=df(u,x)*df(v,x)*a15$
df(u,s)=(df(u,x,5)*a2**2*b2 + 5*df(u,x,3)*df(u,x)*a15*a2*b2 + 5/2*df(u,x,2)**2*
a15*a2*b2 + 5/2*df(u,x)**3*a15**2*b2 + 3*df(u,x)*f(df(v,x),df(v,x))*a15*a7*b2 +
2*f(df(v,x,2),df(v,x,2))*a2*a7*b2 + 2*f(df(v,x),df(v,x,3))*a2*a7*b2)/a2**2$
df(v,s)=(df(u,x,3)*df(v,x)*a15*a2*b2 + 3/2*df(u,x)**2*df(v,x)*a15**2*b2 + df(v,x
)*f(df(v,x),df(v,x))*a15*a7*b2)/a2**2$