Solution 12 to problem l1o35
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Parameters |
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Expressions
The solution is given through the following expressions:
b75=0
b74=0
b73=0
b72=0
b71=0
b70=0
b69=0
b68=0
b67=0
b66=0
b65=0
b64=0
b63=0
b62=0
b61=0
b60=0
b59=0
b58=(5/9*a15*a7*b37)/a13**2
b57=0
b56=0
b55=0
b54=0
b53=0
b52=0
b51=0
b50=0
b49=0
b48=0
b47=0
b46=(5/6*a15**2*b37)/a13**2
b45=0
b44=0
b43=0
b42=0
b41=(5/3*a15*b37)/a13
b40=(5/3*a15*b37)/a13
b39=(5/3*a15*b37)/a13
b38=0
b36=0
b35=0
b34=0
b33=0
b32=0
b31=0
b30=0
b29=0
b28=0
b27=0
b26=0
b25=0
b24=0
b23=0
b22=0
b21=0
b20=0
b19=0
b18=(5/3*a15*a7*b37)/a13**2
b17=0
b16=0
b15=0
b14=(10/3*a7*b37)/a13
b13=(5/3*a7*b37)/a13
b12=0
b11=0
b10=0
b9=0
b8=(5/18*a15**2*b37)/a13**2
b7=0
b6=0
b5=(5/6*a15*b37)/a13
b4=(5/3*a15*b37)/a13
b3=0
b2=b37
a22=0
a21=0
a20=0
a19=0
a18=0
a17=0
a16=0
a14=0
a12=0
a11=0
a10=0
a9=0
a8=0
a6=0
a5=0
a4=1/2*a15
a3=0
a2=a13
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
b37,a7,a15,a13
Relevance for the application:
/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\$
1 2
df(u,t)=u *a13 + ---*u *a15 + f(v ,v )*a7
3x 2 x x x
df(v,t)=u *v *a15 + v *a13
x x 3x
2 5 5 2
df(u,s)=(u *a13 *b37 + ---*u *u *a13*a15*b37 + ---*u *a13*a15*b37
5x 3 3x x 6 2x
5 3 2 5
+ ----*u *a15 *b37 + ---*u *f(v ,v )*a15*a7*b37
18 x 3 x x x
5 10 2
+ ---*f(v ,v )*a13*a7*b37 + ----*f(v ,v )*a13*a7*b37)/a13
3 2x 2x 3 x 3x
5 5 5 2 2
df(v,s)=(---*u *v *a13*a15*b37 + ---*u *v *a13*a15*b37 + ---*u *v *a15 *b37
3 3x x 3 2x 2x 6 x x
5 2 5
+ ---*u *v *a13*a15*b37 + v *a13 *b37 + ---*v *f(v ,v )*a15*a7*b37)/
3 x 3x 5x 9 x x x
2
a13
df(u,t)=df(u,x,3)*a13 + 1/2*df(u,x)**2*a15 + f(df(v,x),df(v,x))*a7$
df(v,t)=df(u,x)*df(v,x)*a15 + df(v,x,3)*a13$
df(u,s)=(df(u,x,5)*a13**2*b37 + 5/3*df(u,x,3)*df(u,x)*a13*a15*b37 + 5/6*df(u,x,2
)**2*a13*a15*b37 + 5/18*df(u,x)**3*a15**2*b37 + 5/3*df(u,x)*f(df(v,x),df(v,x))*
a15*a7*b37 + 5/3*f(df(v,x,2),df(v,x,2))*a13*a7*b37 + 10/3*f(df(v,x),df(v,x,3))*
a13*a7*b37)/a13**2$
df(v,s)=(5/3*df(u,x,3)*df(v,x)*a13*a15*b37 + 5/3*df(u,x,2)*df(v,x,2)*a13*a15*b37
+ 5/6*df(u,x)**2*df(v,x)*a15**2*b37 + 5/3*df(u,x)*df(v,x,3)*a13*a15*b37 + df(v,
x,5)*a13**2*b37 + 5/9*df(v,x)*f(df(v,x),df(v,x))*a15*a7*b37)/a13**2$