Solution 1 to problem N1t5s14f2

Expressions | Parameters | Inequalities | Relevance | Back to problem N1t5s14f2

Expressions

The solution is given through the following expressions:


q14=0


q13=0


q12=0


q11=0


q10=0


q9=0


q8=0


q7=0


q6=0


q4=0


q3=0


q2=0


    4*p1*q5
q1=---------
      p2

Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:

 q5, p2, p1

Inequalities

In the following not identically vanishing expressions are shown. Any auxiliary variables g00?? are used to express that at least one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3 means that either p4 or p3 or both are non-vanishing.

 
{g0014*p2 + 4*g0018*p1,g0019*p2 + g0020*p1}

Relevance for the application:

The equation:


f =Df *f*p1 + Df*f *p2
 t   x            x

The symmetry:

              3               4
    4*Df *(Df) *f*p1*q5 + (Df) *f *p2*q5
        x                        x
f =--------------------------------------
 s                   p2

And now in machine readable form:

The system:

df(f(1),t)=d(1,df(f(1),x))*f(1)*p1 + d(1,f(1))*df(f(1),x)*p2$

The symmetry:

df(f(1),s)=(4*d(1,df(f(1),x))*d(1,f(1))**3*f(1)*p1*q5 + d(1,f(1))**4*df(f(1),x)*
p2*q5)/p2$