Solution 1 to problem over


Remaining equations | Expressions | Parameters | Inequalities | Relevance | Back to problem over

Equations

The following unsolved equations remain:
       2      2
0=4*a23  + a33


Expressions

The solution is given through the following expressions:

r41=0


                1
     a23*r49 - ---*a33*r442
                2
r42=------------------------
              a23


r43=0


r44=0


r45=0


r46=0


r47=0


r48=0


r410=0


r411=0


r412=0


r413=0


       1
      ---*a33*r435
       2
r415=--------------
          a23


r416=0


          1
       - ---*a33*r442
          2
r417=-----------------
            a23


r418=0


r419=0


r420=0


r421=0


       1
      ---*a33*r442
       2
r422=--------------
          a23


r423=0


r424=0


      a23*r4105 + a33*r435
r425=----------------------
              a23


r426=0


r427=0


r428=0


r429=0


r430=0


r431=0


r432=0


r433=0


r434=0


r436=0


r437= - r442


r438=0


r439=0


r440=0


r441=0


r443=0


r444=0


r445=2*r435


r446=0


r447=0


r448=0


r449=0


r451=0


r452=0


r453=0


r454=0


r455=r4105


r456=0


r457=0


r458=0


r459=0


r460=0


r461=0


r462=0


r463=0


r465=0


r466=0


r467=0


r468=0


r469=0


r470=0


r471=0


r472=0


r473=0


r474=0


r475= - 2*r442


r476=0


r477=0


r478=0


r479=0


r480=0


r481=0


r482=0


r483=0


r484=0


r485=0


r486=0


r487=0


r488=0


r489=0


r490=0


r491=0


r492=0


r493=0


r494=0


r495=0


r496=0


r497=0


r498=0


r499=0


r4100=0


r4101=0


r4102=0


r4103=0


r4104=0


r4106=0


r4107=0


r4108=0


r4109=0


r4111=0


r4112=0


r4113=0


r4114=0


r4115=0


r4116=0


r4117=0


r4119=0


r4120=0


r4121=0


r4122=0


r4123=0


r4124=0


c33=0


c23=0


     1
b33=---*a33
     2


b32=0


b23=a23


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 r40, r49, r435, r4105, r442, a33, a23

Inequalities

In the following not identically vanishing expressions are shown. Any auxiliary variables g00?? are used to express that at least one of their coefficients must not vanish, e.g. g0019*p4 + g0020*p3 means that either p4 or p3 or both are non-vanishing.
 
{b33,a33,r442,a23}


Relevance for the application:

Modulo the following equation:

       2      2
0=4*a23  + a33


the system of equations related to the Hamiltonian HAM:

                                2        1
HAM=2*u2*u3*a23 + u2*v3*a23 + u3 *a33 + ---*u3*v3*a33
                                         2

has apart from the Hamiltonian and Casimirs the following 5 first integrals: 

                               2               2           1       2
FI= - 2*u1*v1*v2*v3*a23 + u2*v1 *v3*a23 - u2*v2 *v3*a23 + ---*u3*v1 *v3*a33
                                                           2

       1       2           1    2   2
    - ---*u3*v2 *v3*a33 - ---*v2 *v3 *a33
       2                   2

                                       1
  = a product of the elements of: { - ---,
                                       2

   v3,

                           2              2            2            2
   4*u1*v1*v2*a23 - 2*u2*v1 *a23 + 2*u2*v2 *a23 - u3*v1 *a33 + u3*v2 *a33

        2
    + v2 *v3*a33}

{HAM,FI} = 0



     2   2     2   2     2   2
FI=u1 *v3  + u2 *v3  + u3 *v3

                                           2     2     2
  = a product of the elements of: {v3,v3,u1  + u2  + u3 }

{HAM,FI} = 0



             2            3         2   2        1       3
FI=2*u2*u3*v3 *a23 + u2*v3 *a23 + u3 *v3 *a33 + ---*u3*v3 *a33
                                                 2

                                    1
  = a product of the elements of: {---,
                                    2

   v3,

   v3,

   2*u3 + v3,

   2*u2*a23 + u3*a33}

{HAM,FI} = 0



     2   2     2   2
FI=v1 *v3  + v2 *v3

                                           2     2
  = a product of the elements of: {v3,v3,v1  + v2 }

{HAM,FI} = 0



     4
FI=v3

  = a product of the elements of: {v3,v3,v3,v3}

{HAM,FI} = 0





And again in machine readable form:



HAM=2*u2*u3*a23 + u2*v3*a23 + u3**2*a33 + 1/2*u3*v3*a33$

FI= - 2*u1*v1*v2*v3*a23 + u2*v1**2*v3*a23 - u2*v2**2*v3*a23 + 1/2*u3*v1**2*v3*
a33 - 1/2*u3*v2**2*v3*a33 - 1/2*v2**2*v3**2*a33$

FI=u1**2*v3**2 + u2**2*v3**2 + u3**2*v3**2$

FI=2*u2*u3*v3**2*a23 + u2*v3**3*a23 + u3**2*v3**2*a33 + 1/2*u3*v3**3*a33$

FI=v1**2*v3**2 + v2**2*v3**2$

FI=v3**4$