Solution 45 to problem e3null
Expressions |
Parameters |
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Back to problem e3null
Expressions
The solution is given through the following expressions:
3
a22=---*a33
4
b22=0
b31=0
b32=0
b33=0
c12=0
c13=0
c22=0
c23=0
n1=0
n2=0
m1=0
m2=0
4
---*m3*q1
3
r6=-----------
a33
r5=0
r4=0
r2=0
r1=0
q19=0
q18=0
q16=0
q15=0
4 16 2
- ---*a33*c33*q1 - ----*k1*m3
3 9
q14=---------------------------------
2
a33
q13=0
q12=0
q11=0
q10=0
4 16 2
- ---*a33*c33*q1 - ----*k1*m3
3 9
q9=---------------------------------
2
a33
q8=0
q7=0
q5=0
q4=0
q3=q1
q2=0
32
----*c33*k1*m3
9
p50=----------------
2
a33
p49=0
p48=0
p47=p15
p46=0
p45=0
p44=0
p43=0
p42=0
p41=0
p40=0
p39=0
p38=0
p37=0
p36=0
p35=0
p34=0
8
---*k1*m3
3
p33=-----------
a33
p32=0
8
---*k1*m3
3
p31=-----------
a33
p30=0
p29=0
p28=p15
p27=0
p26=0
p25=0
p24=0
p23=0
p22=0
p21=0
p20=0
p19=0
p18=0
p17=0
p16=0
p14=0
p13=0
p12=0
p11=0
p9=0
p8=0
p7=0
p6=0
p5=0
p4=0
p3=0
p2=0
p1=0
k104=0
k103=0
k101=0
k100=0
32 2
- ----*c33 *k1
9
k99=-----------------
2
a33
k98=0
k97=0
k96=0
k95=0
32 2
- ----*c33 *k1
9
k94=-----------------
2
a33
k93=0
k92=0
k90=0
k89=0
8
---*c33*k1
3
k88=------------
a33
k87=0
8
---*c33*k1
3
k86=------------
a33
k85=0
k84=0
k83=0
k82=0
k81=0
k80=0
k79=0
k78=0
k77=0
k76=0
k75=0
k74=0
k73=0
k72=0
k71=0
k70=0
k69=0
k68=0
k67=0
k66=0
k65=0
k64=0
k63=0
k62=0
k61=0
k60=0
k59=0
k58=0
k57=0
k56=0
16 2
- ----*c33 *k1
9
k55=-----------------
2
a33
k54=0
k53=0
k52=0
k51=0
32 2
- ----*c33 *k1
9
k50=-----------------
2
a33
k49=0
k48=0
k47=0
k46=0
k45=0
k44=0
k43=0
k42=0
k41=0
k40=0
k39=0
k38=0
k37=0
k36=0
k35=0
k34=0
k33=0
k32=0
k31=0
k30=0
k28=0
k27=0
k26=0
16 2
- ----*c33 *k1
9
k25=-----------------
2
a33
k24=0
k23=0
k21=0
k20=0
k19=0
k18=0
k17=0
k16=0
k14=0
k13=0
k12=0
k11=0
k10=0
k9=0
k8=0
k7=0
k6=0
k5=k1
k4=0
k3=2*k1
k2=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
c33,n3,m3,r3,q1,p15,p10,k1,a33
Relevance for the application:
The following expression INT is a first
integral for the Hamiltonian HAM:
2 2 2 2
3*a33*u1 + 3*a33*u2 + 4*a33*u3 + 4*c33*v3 + 4*m3*v3 + 4*n3*u3
HAM=-------------------------------------------------------------------
4
2 4 2 2 2 2 4 2 3
INT=(9*a33 *k1*u1 + 18*a33 *k1*u1 *u2 + 9*a33 *k1*u2 + 9*a33 *p10*u3
2 2 2 2 2 2
+ 9*a33 *p15*u3*v1 + 9*a33 *p15*u3*v2 + 9*a33 *p15*u3*v3
2 2 2 2 2 2 2
+ 9*a33 *q1*u1 + 9*a33 *q1*u2 + 9*a33 *r3*u3 + 24*a33*c33*k1*u1 *v3
2 2 2 2
+ 24*a33*c33*k1*u2 *v3 - 12*a33*c33*q1*v1 - 12*a33*c33*q1*v2
2 2
+ 24*a33*k1*m3*u1 *v3 + 24*a33*k1*m3*u2 *v3 + 12*a33*m3*q1*v3
2 4 2 2 2 2 2 2
- 16*c33 *k1*v1 - 32*c33 *k1*v1 *v2 - 32*c33 *k1*v1 *v3
2 4 2 2 2 3 2 2
- 16*c33 *k1*v2 - 32*c33 *k1*v2 *v3 + 32*c33*k1*m3*v3 - 16*k1*m3 *v1
2 2 2
- 16*k1*m3 *v2 )/(9*a33 )
And again in machine readable form:
HAM=(3*a33*u1**2 + 3*a33*u2**2 + 4*a33*u3**2 + 4*c33*v3**2 + 4*m3*v3 + 4*n3*u3)/
4$
INT=(9*a33**2*k1*u1**4 + 18*a33**2*k1*u1**2*u2**2 + 9*a33**2*k1*u2**4 + 9*a33**2
*p10*u3**3 + 9*a33**2*p15*u3*v1**2 + 9*a33**2*p15*u3*v2**2 + 9*a33**2*p15*u3*v3
**2 + 9*a33**2*q1*u1**2 + 9*a33**2*q1*u2**2 + 9*a33**2*r3*u3 + 24*a33*c33*k1*u1
**2*v3**2 + 24*a33*c33*k1*u2**2*v3**2 - 12*a33*c33*q1*v1**2 - 12*a33*c33*q1*v2**
2 + 24*a33*k1*m3*u1**2*v3 + 24*a33*k1*m3*u2**2*v3 + 12*a33*m3*q1*v3 - 16*c33**2*
k1*v1**4 - 32*c33**2*k1*v1**2*v2**2 - 32*c33**2*k1*v1**2*v3**2 - 16*c33**2*k1*v2
**4 - 32*c33**2*k1*v2**2*v3**2 + 32*c33*k1*m3*v3**3 - 16*k1*m3**2*v1**2 - 16*k1*
m3**2*v2**2)/(9*a33**2)$