Solution 37 to problem e3null


Expressions | Parameters | Relevance | Back to problem e3null

Expressions

The solution is given through the following expressions:

     3
a22=---*a33
     4


b22=0


b31=0


b32=0


b33=0


c12=0


c13=0


c22=0


c23=0


c33=0


n2=0


m1=0


m2=0


m3=0


r6=0


r5=0


r4=0


            2                 2              3            2               3
     - 4*a33 *n3*q1 + 64*k1*n1 *n3 - 64*k1*n3  - 64*k10*n1 *n3 + 64*k10*n3
r3=-------------------------------------------------------------------------
                                        3
                                     a33


r2=0


            2                 3              2            3               2
     - 4*a33 *n1*q1 + 64*k1*n1  - 64*k1*n1*n3  - 64*k10*n1  + 64*k10*n1*n3
r1=-------------------------------------------------------------------------
                                        3
                                     a33


q19=0


q18=0


q16=0


q15=0


q14=0


q13=0


q12=0


q11=0


q10=0


q9=0


q8=0


q7=0


q5=0


    32*k1*n1*n3 - 32*k10*n1*n3
q4=----------------------------
                  2
               a33


       2              2            2
    a33 *q1 - 16*k1*n1  + 16*k10*n1
q3=----------------------------------
                     2
                  a33


q2=0


p50=0


p49=0


p48=0


p47=0


p46=0


p45=0


p44=0


p43=0


p42=0


p41=0


p40=0


p39=0


p38=0


p37=0


p36=0


p35=0


p34=0


p33=0


p32=0


p31=0


p30=0


p29=0


p28=0


p27=0


p26=0


p25=0


p24=0


p23=0


p22=0


p21=0


p20=0


p19=0


p18=0


p17=0


p16=0


p15=0


p14=0


p13=0


p12=0


p11=0


      - 4*k10*n3
p10=-------------
         a33


p9=0


     - 4*k10*n1
p8=-------------
        a33


     - 8*k1*n3 + 4*k10*n3
p7=-----------------------
             a33


p6=0


     - 8*k1*n3 + 4*k10*n3
p5=-----------------------
             a33


p4=0


     - 8*k1*n1 + 4*k10*n1
p3=-----------------------
             a33


p2=0


     - 8*k1*n1 + 4*k10*n1
p1=-----------------------
             a33


k104=0


k103=0


k101=0


k100=0


k99=0


k98=0


k97=0


k96=0


k95=0


k94=0


k93=0


k92=0


k90=0


k89=0


k88=0


k87=0


k86=0


k85=0


k84=0


k83=0


k82=0


k81=0


k80=0


k79=0


k78=0


k77=0


k76=0


k75=0


k74=0


k73=0


k72=0


k71=0


k70=0


k69=0


k68=0


k67=0


k66=0


k65=0


k64=0


k63=0


k62=0


k61=0


k60=0


k59=0


k58=0


k57=0


k56=0


k55=0


k54=0


k53=0


k52=0


k51=0


k50=0


k49=0


k48=0


k47=0


k46=0


k45=0


k44=0


k43=0


k42=0


k41=0


k40=0


k39=0


k38=0


k37=0


k36=0


k35=0


k34=0


k33=0


k32=0


k31=0


k30=0


k28=0


k27=0


k26=0


k25=0


k24=0


k23=0


k21=0


k20=0


k19=0


k18=0


k17=0


k16=0


k14=0


k13=0


k12=k10


k11=0


k9=0


k8=0


k7=0


k6=0


k5=k1


k4=0


k3=2*k1


k2=0


Parameters

Apart from the condition that they must not vanish to give a non-trivial solution and a non-singular solution with non-vanishing denominators, the following parameters are free:
 n3,q1,k1,n1,k10,a33

Relevance for the application:

The following expression INT is a first

integral for the Hamiltonian HAM:

             2           2           2
     3*a33*u1  + 3*a33*u2  + 4*a33*u3  + 4*n1*u1 + 4*n3*u3
HAM=-------------------------------------------------------
                               4

        3      4        3      2   2      3      4      3       2   2
INT=(a33 *k1*u1  + 2*a33 *k1*u1 *u2  + a33 *k1*u2  + a33 *k10*u1 *u3

           3       2   2      3      2      3      2        2         3
      + a33 *k10*u2 *u3  + a33 *q1*u1  + a33 *q1*u2  - 8*a33 *k1*n1*u1

             2            2        2         2           2         2
      - 8*a33 *k1*n1*u1*u2  - 8*a33 *k1*n3*u1 *u3 - 8*a33 *k1*n3*u2 *u3

             2          3        2             2        2             2
      + 4*a33 *k10*n1*u1  + 4*a33 *k10*n1*u1*u2  - 4*a33 *k10*n1*u1*u3

             2          2           2          2           2          3
      + 4*a33 *k10*n3*u1 *u3 + 4*a33 *k10*n3*u2 *u3 - 4*a33 *k10*n3*u3

             2                 2                        2   2
      - 4*a33 *n1*q1*u1 - 4*a33 *n3*q1*u3 - 16*a33*k1*n1 *u2

                                             2   2
      + 32*a33*k1*n1*n3*u1*u3 + 16*a33*k10*n1 *u2  - 32*a33*k10*n1*n3*u1*u3

                3              2                    2              3
      + 64*k1*n1 *u1 + 64*k1*n1 *n3*u3 - 64*k1*n1*n3 *u1 - 64*k1*n3 *u3

                 3               2                     2               3
      - 64*k10*n1 *u1 - 64*k10*n1 *n3*u3 + 64*k10*n1*n3 *u1 + 64*k10*n3 *u3)/

       3
    a33



And again in machine readable form:



HAM=(3*a33*u1**2 + 3*a33*u2**2 + 4*a33*u3**2 + 4*n1*u1 + 4*n3*u3)/4$

INT=(a33**3*k1*u1**4 + 2*a33**3*k1*u1**2*u2**2 + a33**3*k1*u2**4 + a33**3*k10*u1
**2*u3**2 + a33**3*k10*u2**2*u3**2 + a33**3*q1*u1**2 + a33**3*q1*u2**2 - 8*a33**
2*k1*n1*u1**3 - 8*a33**2*k1*n1*u1*u2**2 - 8*a33**2*k1*n3*u1**2*u3 - 8*a33**2*k1*
n3*u2**2*u3 + 4*a33**2*k10*n1*u1**3 + 4*a33**2*k10*n1*u1*u2**2 - 4*a33**2*k10*n1
*u1*u3**2 + 4*a33**2*k10*n3*u1**2*u3 + 4*a33**2*k10*n3*u2**2*u3 - 4*a33**2*k10*
n3*u3**3 - 4*a33**2*n1*q1*u1 - 4*a33**2*n3*q1*u3 - 16*a33*k1*n1**2*u2**2 + 32*
a33*k1*n1*n3*u1*u3 + 16*a33*k10*n1**2*u2**2 - 32*a33*k10*n1*n3*u1*u3 + 64*k1*n1
**3*u1 + 64*k1*n1**2*n3*u3 - 64*k1*n1*n3**2*u1 - 64*k1*n3**3*u3 - 64*k10*n1**3*
u1 - 64*k10*n1**2*n3*u3 + 64*k10*n1*n3**2*u1 + 64*k10*n3**3*u3)/a33**3$