Solution 110 to problem e3null
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Parameters |
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Expressions
The solution is given through the following expressions:
1
a22= - ---*a33
3
b22=0
b31=0
b32=0
b33=0
c12=0
c13=0
c22=0
c23=0
c33=0
n2=0
m1=0
m2=0
m3=0
r6=0
r5=0
r4=0
3 2 27 2 27 3 27 2
r3=( - ---*a33 *n3*q1 + ----*k1*n1 *n3 - ----*k1*n3 - ----*k10*n1 *n3
4 64 64 64
27 3 3
+ ----*k10*n3 )/a33
64
r2=0
3 2 27 3 27 2 27 3
r1=( - ---*a33 *n1*q1 + ----*k1*n1 - ----*k1*n1*n3 - ----*k10*n1
4 64 64 64
27 2 3
+ ----*k10*n1*n3 )/a33
64
q19=0
q18=0
q16=0
q15=0
q14=0
q13=0
q12=0
q11=0
q10=0
q9=0
q8=0
q7=0
q5=0
9 9
---*k1*n1*n3 - ---*k10*n1*n3
8 8
q4=------------------------------
2
a33
2 9 2 9 2
a33 *q1 - ----*k1*n1 + ----*k10*n1
16 16
q3=--------------------------------------
2
a33
q2=0
p50=0
p49=0
p48=0
p47=0
p46=0
p45=0
p44=0
p43=0
p42=0
p41=0
p40=0
p39=0
p38=0
p37=0
p36=0
p35=0
p34=0
p33=0
p32=0
p31=0
p30=0
p29=0
p28=0
p27=0
p26=0
p25=0
p24=0
p23=0
p22=0
p21=0
p20=0
p19=0
p18=0
p17=0
p16=0
p15=0
p14=0
p13=0
p12=0
p11=0
3
- ---*k10*n3
4
p10=---------------
a33
p9=0
3
- ---*k10*n1
4
p8=---------------
a33
3 3
- ---*k1*n3 + ---*k10*n3
2 4
p7=---------------------------
a33
p6=0
3 3
- ---*k1*n3 + ---*k10*n3
2 4
p5=---------------------------
a33
p4=0
3 3
- ---*k1*n1 + ---*k10*n1
2 4
p3=---------------------------
a33
p2=0
3 3
- ---*k1*n1 + ---*k10*n1
2 4
p1=---------------------------
a33
k104=0
k103=0
k101=0
k100=0
k99=0
k98=0
k97=0
k96=0
k95=0
k94=0
k93=0
k92=0
k90=0
k89=0
k88=0
k87=0
k86=0
k85=0
k84=0
k83=0
k82=0
k81=0
k80=0
k79=0
k78=0
k77=0
k76=0
k75=0
k74=0
k73=0
k72=0
k71=0
k70=0
k69=0
k68=0
k67=0
k66=0
k65=0
k64=0
k63=0
k62=0
k61=0
k60=0
k59=0
k58=0
k57=0
k56=0
k55=0
k54=0
k53=0
k52=0
k51=0
k50=0
k49=0
k48=0
k47=0
k46=0
k45=0
k44=0
k43=0
k42=0
k41=0
k40=0
k39=0
k38=0
k37=0
k36=0
k35=0
k34=0
k33=0
k32=0
k31=0
k30=0
k28=0
k27=0
k26=0
k25=0
k24=0
k23=0
k21=0
k20=0
k19=0
k18=0
k17=0
k16=0
k14=0
k13=0
k12=k10
k11=0
k9=0
k8=0
k7=0
k6=0
k5=k1
k4=0
k3=2*k1
k2=0
Parameters
Apart from the condition that they must not vanish to give
a non-trivial solution and a non-singular solution with
non-vanishing denominators, the following parameters are free:
n3,q1,k1,n1,k10,a33
Relevance for the application:
The following expression INT is a first
integral for the Hamiltonian HAM:
2 2 2
- a33*u1 - a33*u2 + 3*a33*u3 + 3*n1*u1 + 3*n3*u3
HAM=------------------------------------------------------
3
3 4 3 2 2 3 4 3 2 2
INT=(64*a33 *k1*u1 + 128*a33 *k1*u1 *u2 + 64*a33 *k1*u2 + 64*a33 *k10*u1 *u3
3 2 2 3 2 3 2
+ 64*a33 *k10*u2 *u3 + 64*a33 *q1*u1 + 64*a33 *q1*u2
2 3 2 2 2 2
- 96*a33 *k1*n1*u1 - 96*a33 *k1*n1*u1*u2 - 96*a33 *k1*n3*u1 *u3
2 2 2 3 2 2
- 96*a33 *k1*n3*u2 *u3 + 48*a33 *k10*n1*u1 + 48*a33 *k10*n1*u1*u2
2 2 2 2 2 2
- 48*a33 *k10*n1*u1*u3 + 48*a33 *k10*n3*u1 *u3 + 48*a33 *k10*n3*u2 *u3
2 3 2 2
- 48*a33 *k10*n3*u3 - 48*a33 *n1*q1*u1 - 48*a33 *n3*q1*u3
2 2 2 2
- 36*a33*k1*n1 *u2 + 72*a33*k1*n1*n3*u1*u3 + 36*a33*k10*n1 *u2
3 2
- 72*a33*k10*n1*n3*u1*u3 + 27*k1*n1 *u1 + 27*k1*n1 *n3*u3
2 3 3 2
- 27*k1*n1*n3 *u1 - 27*k1*n3 *u3 - 27*k10*n1 *u1 - 27*k10*n1 *n3*u3
2 3 3
+ 27*k10*n1*n3 *u1 + 27*k10*n3 *u3)/(64*a33 )
And again in machine readable form:
HAM=( - a33*u1**2 - a33*u2**2 + 3*a33*u3**2 + 3*n1*u1 + 3*n3*u3)/3$
INT=(64*a33**3*k1*u1**4 + 128*a33**3*k1*u1**2*u2**2 + 64*a33**3*k1*u2**4 + 64*
a33**3*k10*u1**2*u3**2 + 64*a33**3*k10*u2**2*u3**2 + 64*a33**3*q1*u1**2 + 64*a33
**3*q1*u2**2 - 96*a33**2*k1*n1*u1**3 - 96*a33**2*k1*n1*u1*u2**2 - 96*a33**2*k1*
n3*u1**2*u3 - 96*a33**2*k1*n3*u2**2*u3 + 48*a33**2*k10*n1*u1**3 + 48*a33**2*k10*
n1*u1*u2**2 - 48*a33**2*k10*n1*u1*u3**2 + 48*a33**2*k10*n3*u1**2*u3 + 48*a33**2*
k10*n3*u2**2*u3 - 48*a33**2*k10*n3*u3**3 - 48*a33**2*n1*q1*u1 - 48*a33**2*n3*q1*
u3 - 36*a33*k1*n1**2*u2**2 + 72*a33*k1*n1*n3*u1*u3 + 36*a33*k10*n1**2*u2**2 - 72
*a33*k10*n1*n3*u1*u3 + 27*k1*n1**3*u1 + 27*k1*n1**2*n3*u3 - 27*k1*n1*n3**2*u1 -
27*k1*n3**3*u3 - 27*k10*n1**3*u1 - 27*k10*n1**2*n3*u3 + 27*k10*n1*n3**2*u1 + 27*
k10*n3**3*u3)/(64*a33**3)$